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14341032512403 = 331279155250681
BaseRepresentation
bin1101000010110000100000…
…1001100000101110010011
31212202222201012202120202020
43100230020021200232103
53334430413310344103
650300102425222523
73010051104026112
oct320541011405623
955688635676666
1014341032512403
114629aa7a8a863
12173747a931a43
13800479a1699c
14378176d4dc79
1519d09aa48753
hexd0b08260b93

14341032512403 has 16 divisors (see below), whose sum is σ = 19745267730432. Its totient is φ = 9248963832000.

The previous prime is 14341032512381. The next prime is 14341032512419. The reversal of 14341032512403 is 30421523014341.

It is not a de Polignac number, because 14341032512403 - 220 = 14341031463827 is a prime.

It is not an unprimeable number, because it can be changed into a prime (14341032512453) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 27365778 + ... + 27884903.

It is an arithmetic number, because the mean of its divisors is an integer number (1234079233152).

Almost surely, 214341032512403 is an apocalyptic number.

14341032512403 is a deficient number, since it is larger than the sum of its proper divisors (5404235218029).

14341032512403 is a wasteful number, since it uses less digits than its factorization.

14341032512403 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 55253506.

The product of its (nonzero) digits is 34560, while the sum is 33.

Adding to 14341032512403 its reverse (30421523014341), we get a palindrome (44762555526744).

The spelling of 14341032512403 in words is "fourteen trillion, three hundred forty-one billion, thirty-two million, five hundred twelve thousand, four hundred three".

Divisors: 1 3 31 93 2791 8373 86521 259563 55250681 165752043 1712771111 5138313333 154204650671 462613952013 4780344170801 14341032512403