Base | Representation |
---|---|
bin | 1101000010101101001100… |
… | …1101110000111101011011 |
3 | 1212202220102022200120121212 |
4 | 3100223103031300331123 |
5 | 3334422103433410120 |
6 | 50255434342453335 |
7 | 3010020101345216 |
oct | 320532315607533 |
9 | 55686368616555 |
10 | 14340144435035 |
11 | 4629691761121 |
12 | 173727143424b |
13 | 800367a36013 |
14 | 3780d101877d |
15 | 19d047ac46c5 |
hex | d0ad3370f5b |
14340144435035 has 16 divisors (see below), whose sum is σ = 17319283387776. Its totient is φ = 11398131374208.
The previous prime is 14340144435017. The next prime is 14340144435121. The reversal of 14340144435035 is 53053444104341.
It is a cyclic number.
It is not a de Polignac number, because 14340144435035 - 232 = 14335849467739 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 14340144434983 and 14340144435001.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 4288124 + ... + 6860633.
It is an arithmetic number, because the mean of its divisors is an integer number (1082455211736).
Almost surely, 214340144435035 is an apocalyptic number.
14340144435035 is a deficient number, since it is larger than the sum of its proper divisors (2979138952741).
14340144435035 is a wasteful number, since it uses less digits than its factorization.
14340144435035 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 11150422.
The product of its (nonzero) digits is 691200, while the sum is 41.
Adding to 14340144435035 its reverse (53053444104341), we get a palindrome (67393588539376).
The spelling of 14340144435035 in words is "fourteen trillion, three hundred forty billion, one hundred forty-four million, four hundred thirty-five thousand, thirty-five".
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