Base | Representation |
---|---|
bin | 10100110110000100010… |
… | …001100110000011101011 |
3 | 12001221101102210221010022 |
4 | 110312010101212003223 |
5 | 141432120442030121 |
6 | 3014015543311055 |
7 | 205330165163354 |
oct | 24660421460353 |
9 | 5057342727108 |
10 | 1432443314411 |
11 | 50254a9a862a |
12 | 1b174a44b48b |
13 | a5104241c35 |
14 | 4d48b34ad2b |
15 | 273db518aab |
hex | 14d844660eb |
1432443314411 has 2 divisors, whose sum is σ = 1432443314412. Its totient is φ = 1432443314410.
The previous prime is 1432443314383. The next prime is 1432443314437. The reversal of 1432443314411 is 1144133442341.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1432443314411 is a prime.
It is not a weakly prime, because it can be changed into another prime (1432443314311) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 716221657205 + 716221657206.
It is an arithmetic number, because the mean of its divisors is an integer number (716221657206).
Almost surely, 21432443314411 is an apocalyptic number.
1432443314411 is a deficient number, since it is larger than the sum of its proper divisors (1).
1432443314411 is an equidigital number, since it uses as much as digits as its factorization.
1432443314411 is an evil number, because the sum of its binary digits is even.
The product of its digits is 55296, while the sum is 35.
Adding to 1432443314411 its reverse (1144133442341), we get a palindrome (2576576756752).
The spelling of 1432443314411 in words is "one trillion, four hundred thirty-two billion, four hundred forty-three million, three hundred fourteen thousand, four hundred eleven".
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