Base | Representation |
---|---|
bin | 1101000001110001110100… |
… | …0110101011011100101110 |
3 | 1212201101021102100212110201 |
4 | 3100130131012223130232 |
5 | 3334141432240103004 |
6 | 50244240520424114 |
7 | 3005614063644523 |
oct | 320343506533456 |
9 | 55641242325421 |
10 | 14324204222254 |
11 | 4622951941353 |
12 | 173416301803a |
13 | 7cb9c7483c54 |
14 | 37741bdab14a |
15 | 19c91348d6a4 |
hex | d071d1ab72e |
14324204222254 has 4 divisors (see below), whose sum is σ = 21486306333384. Its totient is φ = 7162102111126.
The previous prime is 14324204222213. The next prime is 14324204222291. The reversal of 14324204222254 is 45222240242341.
It is a semiprime because it is the product of two primes.
It is a super-3 number, since 3×143242042222543 (a number of 40 digits) contains 333 as substring.
It is a congruent number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3581051055562 + ... + 3581051055565.
It is an arithmetic number, because the mean of its divisors is an integer number (5371576583346).
Almost surely, 214324204222254 is an apocalyptic number.
14324204222254 is a deficient number, since it is larger than the sum of its proper divisors (7162102111130).
14324204222254 is an equidigital number, since it uses as much as digits as its factorization.
14324204222254 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 7162102111129.
The product of its (nonzero) digits is 245760, while the sum is 37.
Adding to 14324204222254 its reverse (45222240242341), we get a palindrome (59546444464595).
The spelling of 14324204222254 in words is "fourteen trillion, three hundred twenty-four billion, two hundred four million, two hundred twenty-two thousand, two hundred fifty-four".
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