Search a number
-
+
143113 is a prime number
BaseRepresentation
bin100010111100001001
321021022111
4202330021
514034423
63022321
71134145
oct427411
9237274
10143113
1198583
126a9a1
13501a9
143a225
152c60d
hex22f09

143113 has 2 divisors, whose sum is σ = 143114. Its totient is φ = 143112.

The previous prime is 143111. The next prime is 143137. The reversal of 143113 is 311341.

143113 = 2672 + 2682.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 71824 + 71289 = 268^2 + 267^2 .

It is an emirp because it is prime and its reverse (311341) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 143113 - 21 = 143111 is a prime.

Together with 143111, it forms a pair of twin primes.

It is a junction number, because it is equal to n+sod(n) for n = 143093 and 143102.

It is not a weakly prime, because it can be changed into another prime (143111) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 71556 + 71557.

It is an arithmetic number, because the mean of its divisors is an integer number (71557).

2143113 is an apocalyptic number.

143113 is the 268-th centered square number.

It is an amenable number.

143113 is a deficient number, since it is larger than the sum of its proper divisors (1).

143113 is an equidigital number, since it uses as much as digits as its factorization.

143113 is an evil number, because the sum of its binary digits is even.

The product of its digits is 36, while the sum is 13.

The square root of 143113 is about 378.3027887817. The cubic root of 143113 is about 52.3069858946.

Adding to 143113 its reverse (311341), we get a palindrome (454454).

It can be divided in two parts, 1431 and 13, that added together give a square (1444 = 382).

The spelling of 143113 in words is "one hundred forty-three thousand, one hundred thirteen".