Base | Representation |
---|---|
bin | 1100111101000011110011… |
… | …1010000101011010001011 |
3 | 1212102122000110100001022212 |
4 | 3033100330322011122023 |
5 | 3331324414123204003 |
6 | 50143112151535335 |
7 | 3000014060305205 |
oct | 317207472053213 |
9 | 55378013301285 |
10 | 14243133413003 |
11 | 45a152a548450 |
12 | 17204b868a54b |
13 | 7c417754bcc1 |
14 | 37352ad31775 |
15 | 19a76aea2dd8 |
hex | cf43ce8568b |
14243133413003 has 4 divisors (see below), whose sum is σ = 15537963723288. Its totient is φ = 12948303102720.
The previous prime is 14243133412919. The next prime is 14243133413009. The reversal of 14243133413003 is 30031433134241.
It is a happy number.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 14243133413003 - 28 = 14243133412747 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (14243133413009) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 647415155126 + ... + 647415155147.
It is an arithmetic number, because the mean of its divisors is an integer number (3884490930822).
Almost surely, 214243133413003 is an apocalyptic number.
14243133413003 is a deficient number, since it is larger than the sum of its proper divisors (1294830310285).
14243133413003 is a wasteful number, since it uses less digits than its factorization.
14243133413003 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1294830310284.
The product of its (nonzero) digits is 31104, while the sum is 32.
Adding to 14243133413003 its reverse (30031433134241), we get a palindrome (44274566547244).
The spelling of 14243133413003 in words is "fourteen trillion, two hundred forty-three billion, one hundred thirty-three million, four hundred thirteen thousand, three".
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