Base | Representation |
---|---|
bin | 100000010100010011001111… |
… | …001101111111011011001011 |
3 | 200122020201220200202221202202 |
4 | 200110103033031333123023 |
5 | 122112144412240414403 |
6 | 1222142441310150415 |
7 | 41636510461611134 |
oct | 4024231715773313 |
9 | 618221820687682 |
10 | 142132534310603 |
11 | 4131908425a231 |
12 | 13b362a21b240b |
13 | 614006abcca65 |
14 | 2715373a68c8b |
15 | 11672d7a84688 |
hex | 8144cf37f6cb |
142132534310603 has 2 divisors, whose sum is σ = 142132534310604. Its totient is φ = 142132534310602.
The previous prime is 142132534310519. The next prime is 142132534310609. The reversal of 142132534310603 is 306013435231241.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 142132534310603 - 222 = 142132530116299 is a prime.
It is not a weakly prime, because it can be changed into another prime (142132534310609) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 71066267155301 + 71066267155302.
It is an arithmetic number, because the mean of its divisors is an integer number (71066267155302).
Almost surely, 2142132534310603 is an apocalyptic number.
142132534310603 is a deficient number, since it is larger than the sum of its proper divisors (1).
142132534310603 is an equidigital number, since it uses as much as digits as its factorization.
142132534310603 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 155520, while the sum is 38.
Adding to 142132534310603 its reverse (306013435231241), we get a palindrome (448145969541844).
The spelling of 142132534310603 in words is "one hundred forty-two trillion, one hundred thirty-two billion, five hundred thirty-four million, three hundred ten thousand, six hundred three".
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