Base | Representation |
---|---|
bin | 100000010100010011001111… |
… | …001101111101100101000100 |
3 | 200122020201220200202120101210 |
4 | 200110103033031331211010 |
5 | 122112144412240144134 |
6 | 1222142441310051420 |
7 | 41636510461550115 |
oct | 4024231715754504 |
9 | 618221820676353 |
10 | 142132534303044 |
11 | 4131908425458a |
12 | 13b362a21a9b70 |
13 | 614006abc949c |
14 | 2715373a6620c |
15 | 11672d7a822e9 |
hex | 8144cf37d944 |
142132534303044 has 24 divisors (see below), whose sum is σ = 335840587384960. Its totient is φ = 46777796099424.
The previous prime is 142132534302989. The next prime is 142132534303163. The reversal of 142132534303044 is 440303435231241.
It is a junction number, because it is equal to n+sod(n) for n = 142132534302993 and 142132534303011.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 74964415879 + ... + 74964417774.
Almost surely, 2142132534303044 is an apocalyptic number.
It is an amenable number.
142132534303044 is an abundant number, since it is smaller than the sum of its proper divisors (193708053081916).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
142132534303044 is a wasteful number, since it uses less digits than its factorization.
142132534303044 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 149928833739 (or 149928833737 counting only the distinct ones).
The product of its (nonzero) digits is 414720, while the sum is 39.
Adding to 142132534303044 its reverse (440303435231241), we get a palindrome (582435969534285).
The spelling of 142132534303044 in words is "one hundred forty-two trillion, one hundred thirty-two billion, five hundred thirty-four million, three hundred three thousand, forty-four".
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