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142132534303044 = 22379149928833653
BaseRepresentation
bin100000010100010011001111…
…001101111101100101000100
3200122020201220200202120101210
4200110103033031331211010
5122112144412240144134
61222142441310051420
741636510461550115
oct4024231715754504
9618221820676353
10142132534303044
114131908425458a
1213b362a21a9b70
13614006abc949c
142715373a6620c
1511672d7a822e9
hex8144cf37d944

142132534303044 has 24 divisors (see below), whose sum is σ = 335840587384960. Its totient is φ = 46777796099424.

The previous prime is 142132534302989. The next prime is 142132534303163. The reversal of 142132534303044 is 440303435231241.

It is a junction number, because it is equal to n+sod(n) for n = 142132534302993 and 142132534303011.

It is an unprimeable number.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 74964415879 + ... + 74964417774.

Almost surely, 2142132534303044 is an apocalyptic number.

It is an amenable number.

142132534303044 is an abundant number, since it is smaller than the sum of its proper divisors (193708053081916).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

142132534303044 is a wasteful number, since it uses less digits than its factorization.

142132534303044 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 149928833739 (or 149928833737 counting only the distinct ones).

The product of its (nonzero) digits is 414720, while the sum is 39.

Adding to 142132534303044 its reverse (440303435231241), we get a palindrome (582435969534285).

The spelling of 142132534303044 in words is "one hundred forty-two trillion, one hundred thirty-two billion, five hundred thirty-four million, three hundred three thousand, forty-four".

Divisors: 1 2 3 4 6 12 79 158 237 316 474 948 149928833653 299857667306 449786500959 599715334612 899573001918 1799146003836 11844377858587 23688755717174 35533133575761 47377511434348 71066267151522 142132534303044