Base | Representation |
---|---|
bin | 11010010100011011… |
… | …10111101111001011 |
3 | 1100110202012000102212 |
4 | 31022031313233023 |
5 | 212414243131133 |
6 | 10254040015335 |
7 | 1010104314002 |
oct | 151215675713 |
9 | 40422160385 |
10 | 14130052043 |
11 | 5aa1056268 |
12 | 28a416154b |
13 | 1442545253 |
14 | 98088bc39 |
15 | 57a772148 |
hex | 34a377bcb |
14130052043 has 2 divisors, whose sum is σ = 14130052044. Its totient is φ = 14130052042.
The previous prime is 14130052037. The next prime is 14130052051. The reversal of 14130052043 is 34025003141.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 14130052043 - 28 = 14130051787 is a prime.
It is not a weakly prime, because it can be changed into another prime (14130252043) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7065026021 + 7065026022.
It is an arithmetic number, because the mean of its divisors is an integer number (7065026022).
Almost surely, 214130052043 is an apocalyptic number.
14130052043 is a deficient number, since it is larger than the sum of its proper divisors (1).
14130052043 is an equidigital number, since it uses as much as digits as its factorization.
14130052043 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1440, while the sum is 23.
Adding to 14130052043 its reverse (34025003141), we get a palindrome (48155055184).
The spelling of 14130052043 in words is "fourteen billion, one hundred thirty million, fifty-two thousand, forty-three".
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