14123403401 has 2 divisors, whose sum is σ = 14123403402. Its totient is φ = 14123403400.

The previous prime is 14123403397. The next prime is 14123403403. The reversal of 14123403401 is 10430432141.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 12967743376 + 1155660025 = 113876^2 + 33995^2 .

It is a cyclic number.

It is not a de Polignac number, because 14123403401 - 2² = 14123403397 is a prime.

Together with 14123403403, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (14123403403) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7061701700 + 7061701701.

It is an arithmetic number, because the mean of its divisors is an integer number (7061701701).

Almost surely, 2^14123403401 is an apocalyptic number.

It is an amenable number.

14123403401 is a deficient number, since it is larger than the sum of its proper divisors (1).

14123403401 is an equidigital number, since it uses as much as digits as its factorization.

14123403401 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1152, while the sum is 23.

Adding to 14123403401 its reverse (10430432141), we get a palindrome (24553835542).

The spelling of 14123403401 in words is "fourteen billion, one hundred twenty-three million, four hundred three thousand, four hundred one".