141215003251341 has 4 divisors (see below), whose sum is σ = 188286671001792. Its totient is φ = 94143335500892.

The previous prime is 141215003251321. The next prime is 141215003251381. The reversal of 141215003251341 is 143152300512141.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 141215003251341 - 2⁹ = 141215003250829 is a prime.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (141215003251321) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 23535833875221 + ... + 23535833875226.

It is an arithmetic number, because the mean of its divisors is an integer number (47071667750448).

Almost surely, 2^{141215003251341} is an apocalyptic number.

It is an amenable number.

141215003251341 is a deficient number, since it is larger than the sum of its proper divisors (47071667750451).

141215003251341 is an equidigital number, since it uses as much as digits as its factorization.

141215003251341 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 47071667750450.

The product of its (nonzero) digits is 14400, while the sum is 33.

Adding to 141215003251341 its reverse (143152300512141), we get a palindrome (284367303763482).

The spelling of 141215003251341 in words is "one hundred forty-one trillion, two hundred fifteen billion, three million, two hundred fifty-one thousand, three hundred forty-one".