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14032000201 is a prime number
BaseRepresentation
bin11010001000101111…
…10101010011001001
31100012220200110121011
431010113311103021
5212214143001301
610240214243521
71004504014402
oct150427652311
940186613534
1014032000201
115a5077548a
1228773565a1
1314281343cb
149718469a9
15571d54a51
hex3445f54c9

14032000201 has 2 divisors, whose sum is σ = 14032000202. Its totient is φ = 14032000200.

The previous prime is 14032000193. The next prime is 14032000207. The reversal of 14032000201 is 10200023041.

14032000201 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 11739505801 + 2292494400 = 108349^2 + 47880^2 .

It is a cyclic number.

It is not a de Polignac number, because 14032000201 - 23 = 14032000193 is a prime.

It is not a weakly prime, because it can be changed into another prime (14032000207) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7016000100 + 7016000101.

It is an arithmetic number, because the mean of its divisors is an integer number (7016000101).

Almost surely, 214032000201 is an apocalyptic number.

It is an amenable number.

14032000201 is a deficient number, since it is larger than the sum of its proper divisors (1).

14032000201 is an equidigital number, since it uses as much as digits as its factorization.

14032000201 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 48, while the sum is 13.

Adding to 14032000201 its reverse (10200023041), we get a palindrome (24232023242).

The spelling of 14032000201 in words is "fourteen billion, thirty-two million, two hundred one", and thus it is an aban number.