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1360452446131 is a prime number
BaseRepresentation
bin10011110011000001010…
…010001110011110110011
311211001120021021220101111
4103303001102032132303
5134242201311234011
62520552213214151
7200201164664122
oct23630122163663
94731507256344
101360452446131
11484a67a36779
1219b7b8931357
139b3a04c981c
1449bbc175ab9
15255c624b121
hex13cc148e7b3

1360452446131 has 2 divisors, whose sum is σ = 1360452446132. Its totient is φ = 1360452446130.

The previous prime is 1360452446039. The next prime is 1360452446153. The reversal of 1360452446131 is 1316442540631.

It is a strong prime.

It is an emirp because it is prime and its reverse (1316442540631) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1360452446131 - 211 = 1360452444083 is a prime.

It is a super-2 number, since 2×13604524461312 (a number of 25 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (1360452446191) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 680226223065 + 680226223066.

It is an arithmetic number, because the mean of its divisors is an integer number (680226223066).

Almost surely, 21360452446131 is an apocalyptic number.

1360452446131 is a deficient number, since it is larger than the sum of its proper divisors (1).

1360452446131 is an equidigital number, since it uses as much as digits as its factorization.

1360452446131 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 207360, while the sum is 40.

Adding to 1360452446131 its reverse (1316442540631), we get a palindrome (2676894986762).

The spelling of 1360452446131 in words is "one trillion, three hundred sixty billion, four hundred fifty-two million, four hundred forty-six thousand, one hundred thirty-one".