Base | Representation |
---|---|
bin | 10011110011000001010… |
… | …010001110011110110011 |
3 | 11211001120021021220101111 |
4 | 103303001102032132303 |
5 | 134242201311234011 |
6 | 2520552213214151 |
7 | 200201164664122 |
oct | 23630122163663 |
9 | 4731507256344 |
10 | 1360452446131 |
11 | 484a67a36779 |
12 | 19b7b8931357 |
13 | 9b3a04c981c |
14 | 49bbc175ab9 |
15 | 255c624b121 |
hex | 13cc148e7b3 |
1360452446131 has 2 divisors, whose sum is σ = 1360452446132. Its totient is φ = 1360452446130.
The previous prime is 1360452446039. The next prime is 1360452446153. The reversal of 1360452446131 is 1316442540631.
It is a strong prime.
It is an emirp because it is prime and its reverse (1316442540631) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 1360452446131 - 211 = 1360452444083 is a prime.
It is a super-2 number, since 2×13604524461312 (a number of 25 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (1360452446191) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 680226223065 + 680226223066.
It is an arithmetic number, because the mean of its divisors is an integer number (680226223066).
Almost surely, 21360452446131 is an apocalyptic number.
1360452446131 is a deficient number, since it is larger than the sum of its proper divisors (1).
1360452446131 is an equidigital number, since it uses as much as digits as its factorization.
1360452446131 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 207360, while the sum is 40.
Adding to 1360452446131 its reverse (1316442540631), we get a palindrome (2676894986762).
The spelling of 1360452446131 in words is "one trillion, three hundred sixty billion, four hundred fifty-two million, four hundred forty-six thousand, one hundred thirty-one".
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