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135534305441 is a prime number
BaseRepresentation
bin111111000111001111…
…0010110000010100001
3110221211121201002110102
41332032132112002201
54210033240233231
6142132534312145
712535444405433
oct1761636260241
9427747632412
10135534305441
1152530644787
12223261b8655
13ca1c63a092
1467ba4d2653
1537d3b5cacb
hex1f8e7960a1

135534305441 has 2 divisors, whose sum is σ = 135534305442. Its totient is φ = 135534305440.

The previous prime is 135534305419. The next prime is 135534305449. The reversal of 135534305441 is 144503435531.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 68092293025 + 67442012416 = 260945^2 + 259696^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-135534305441 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 135534305395 and 135534305404.

It is not a weakly prime, because it can be changed into another prime (135534305449) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67767152720 + 67767152721.

It is an arithmetic number, because the mean of its divisors is an integer number (67767152721).

Almost surely, 2135534305441 is an apocalyptic number.

It is an amenable number.

135534305441 is a deficient number, since it is larger than the sum of its proper divisors (1).

135534305441 is an equidigital number, since it uses as much as digits as its factorization.

135534305441 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 216000, while the sum is 38.

The spelling of 135534305441 in words is "one hundred thirty-five billion, five hundred thirty-four million, three hundred five thousand, four hundred forty-one".