Base | Representation |
---|---|
bin | 11001001101011101… |
… | …00100010101001011 |
3 | 1021221020211010111202 |
4 | 30212232210111023 |
5 | 210204332043111 |
6 | 10115010214415 |
7 | 656254400063 |
oct | 144656442513 |
9 | 37836733452 |
10 | 13534643531 |
11 | 5815a54012 |
12 | 275888440b |
13 | 1379096516 |
14 | 92577c3a3 |
15 | 54335eb3b |
hex | 326ba454b |
13534643531 has 4 divisors (see below), whose sum is σ = 13535341152. Its totient is φ = 13533945912.
The previous prime is 13534643527. The next prime is 13534643557.
13534643531 is nontrivially palindromic in base 10.
13534643531 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 13534643531 - 22 = 13534643527 is a prime.
It is a super-2 number, since 2×135346435312 (a number of 21 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (13534643581) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 318851 + ... + 358796.
It is an arithmetic number, because the mean of its divisors is an integer number (3383835288).
Almost surely, 213534643531 is an apocalyptic number.
13534643531 is a deficient number, since it is larger than the sum of its proper divisors (697621).
13534643531 is an equidigital number, since it uses as much as digits as its factorization.
13534643531 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 697620.
The product of its digits is 194400, while the sum is 38.
The spelling of 13534643531 in words is "thirteen billion, five hundred thirty-four million, six hundred forty-three thousand, five hundred thirty-one".
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