13531412121 has 4 divisors (see below), whose sum is σ = 18041882832. Its totient is φ = 9020941412.

The previous prime is 13531412119. The next prime is 13531412131. The reversal of 13531412121 is 12121413531.

13531412121 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 12121413531 = 3 ⋅4040471177.

It is a cyclic number.

It is not a de Polignac number, because 13531412121 - 2¹ = 13531412119 is a prime.

It is a super-2 number, since 2×13531412121² (a number of 21 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 13531412091 and 13531412100.

It is not an unprimeable number, because it can be changed into a prime (13531412131) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2255235351 + ... + 2255235356.

It is an arithmetic number, because the mean of its divisors is an integer number (4510470708).

Almost surely, 2^13531412121 is an apocalyptic number.

It is an amenable number.

13531412121 is a deficient number, since it is larger than the sum of its proper divisors (4510470711).

13531412121 is an equidigital number, since it uses as much as digits as its factorization.

13531412121 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 4510470710.

The product of its digits is 720, while the sum is 24.

Adding to 13531412121 its reverse (12121413531), we get a palindrome (25652825652).

The spelling of 13531412121 in words is "thirteen billion, five hundred thirty-one million, four hundred twelve thousand, one hundred twenty-one".