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13531412107 is a prime number
BaseRepresentation
bin11001001101000100…
…01111011010001011
31021221000201221211101
430212202033122023
5210203020141412
610114413042231
7656215051033
oct144642173213
937830657741
1013531412107
115814147214
122757786377
131378504735
1492517a8c3
15542e22457
hex32688f68b

13531412107 has 2 divisors, whose sum is σ = 13531412108. Its totient is φ = 13531412106.

The previous prime is 13531412029. The next prime is 13531412119. The reversal of 13531412107 is 70121413531.

13531412107 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 13531412107 - 223 = 13523023499 is a prime.

It is a super-2 number, since 2×135314121072 (a number of 21 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (13531412207) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6765706053 + 6765706054.

It is an arithmetic number, because the mean of its divisors is an integer number (6765706054).

Almost surely, 213531412107 is an apocalyptic number.

13531412107 is a deficient number, since it is larger than the sum of its proper divisors (1).

13531412107 is an equidigital number, since it uses as much as digits as its factorization.

13531412107 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 2520, while the sum is 28.

Adding to 13531412107 its reverse (70121413531), we get a palindrome (83652825638).

The spelling of 13531412107 in words is "thirteen billion, five hundred thirty-one million, four hundred twelve thousand, one hundred seven".