Base | Representation |
---|---|
bin | 10011100011111011010… |
… | …001110010100010011001 |
3 | 11202111201210010211010112 |
4 | 103203323101302202121 |
5 | 134011003324303032 |
6 | 2505312103054105 |
7 | 166055441366651 |
oct | 23437321624231 |
9 | 4674653124115 |
10 | 1344245541017 |
11 | 479100622015 |
12 | 198635141335 |
13 | 999b990c342 |
14 | 490c1945361 |
15 | 24e784d51b2 |
hex | 138fb472899 |
1344245541017 has 2 divisors, whose sum is σ = 1344245541018. Its totient is φ = 1344245541016.
The previous prime is 1344245540951. The next prime is 1344245541031. The reversal of 1344245541017 is 7101455424431.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 894895188121 + 449350352896 = 945989^2 + 670336^2 .
It is a cyclic number.
It is not a de Polignac number, because 1344245541017 - 222 = 1344241346713 is a prime.
It is a super-3 number, since 3×13442455410173 (a number of 37 digits) contains 333 as substring.
It is not a weakly prime, because it can be changed into another prime (1344245541047) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 672122770508 + 672122770509.
It is an arithmetic number, because the mean of its divisors is an integer number (672122770509).
Almost surely, 21344245541017 is an apocalyptic number.
It is an amenable number.
1344245541017 is a deficient number, since it is larger than the sum of its proper divisors (1).
1344245541017 is an equidigital number, since it uses as much as digits as its factorization.
1344245541017 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 268800, while the sum is 41.
The spelling of 1344245541017 in words is "one trillion, three hundred forty-four billion, two hundred forty-five million, five hundred forty-one thousand, seventeen".
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