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1344245540551 is a prime number
BaseRepresentation
bin10011100011111011010…
…001110010011011000111
311202111201210010210111021
4103203323101302123013
5134011003324244201
62505312103052011
7166055441365414
oct23437321623307
94674653123437
101344245540551
11479100621731
12198635141007
13999b990c074
14490c194510b
1524e784d4ea1
hex138fb4726c7

1344245540551 has 2 divisors, whose sum is σ = 1344245540552. Its totient is φ = 1344245540550.

The previous prime is 1344245540549. The next prime is 1344245540611. The reversal of 1344245540551 is 1550455424431.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 1344245540551 - 21 = 1344245540549 is a prime.

Together with 1344245540549, it forms a pair of twin primes.

It is a junction number, because it is equal to n+sod(n) for n = 1344245540498 and 1344245540507.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1344245540851) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 672122770275 + 672122770276.

It is an arithmetic number, because the mean of its divisors is an integer number (672122770276).

Almost surely, 21344245540551 is an apocalyptic number.

1344245540551 is a deficient number, since it is larger than the sum of its proper divisors (1).

1344245540551 is an equidigital number, since it uses as much as digits as its factorization.

1344245540551 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 960000, while the sum is 43.

The spelling of 1344245540551 in words is "one trillion, three hundred forty-four billion, two hundred forty-five million, five hundred forty thousand, five hundred fifty-one".