13441323433 has 4 divisors (see below), whose sum is σ = 13497563520. Its totient is φ = 13385083348.

The previous prime is 13441323397. The next prime is 13441323443. The reversal of 13441323433 is 33432314431.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 33432314431 = 103 ⋅324585577.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-13441323433 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 13441323395 and 13441323404.

It is not an unprimeable number, because it can be changed into a prime (13441323443) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 28119685 + ... + 28120162.

It is an arithmetic number, because the mean of its divisors is an integer number (3374390880).

Almost surely, 2^13441323433 is an apocalyptic number.

It is an amenable number.

13441323433 is a deficient number, since it is larger than the sum of its proper divisors (56240087).

13441323433 is an equidigital number, since it uses as much as digits as its factorization.

13441323433 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 56240086.

The product of its digits is 31104, while the sum is 31.

Adding to 13441323433 its reverse (33432314431), we get a palindrome (46873637864).

The spelling of 13441323433 in words is "thirteen billion, four hundred forty-one million, three hundred twenty-three thousand, four hundred thirty-three".