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134343253181 is a prime number
BaseRepresentation
bin111110100011101111…
…0110101110010111101
3110211202121112100220202
41331013132311302331
54200113333100211
6141414430053245
712464102545034
oct1750736656275
9424677470822
10134343253181
1151a7a29a575
122205334a225
13c88c959527
14670625171b
1537642dd53b
hex1f477b5cbd

134343253181 has 2 divisors, whose sum is σ = 134343253182. Its totient is φ = 134343253180.

The previous prime is 134343253063. The next prime is 134343253243. The reversal of 134343253181 is 181352343431.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 129246721081 + 5096532100 = 359509^2 + 71390^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-134343253181 is a prime.

It is a super-2 number, since 2×1343432531812 (a number of 23 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (134343253381) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67171626590 + 67171626591.

It is an arithmetic number, because the mean of its divisors is an integer number (67171626591).

Almost surely, 2134343253181 is an apocalyptic number.

It is an amenable number.

134343253181 is a deficient number, since it is larger than the sum of its proper divisors (1).

134343253181 is an equidigital number, since it uses as much as digits as its factorization.

134343253181 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 103680, while the sum is 38.

The spelling of 134343253181 in words is "one hundred thirty-four billion, three hundred forty-three million, two hundred fifty-three thousand, one hundred eighty-one".