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13431422303311 = 37363011413603
BaseRepresentation
bin1100001101110011111100…
…1001111011110001001111
31202120000211220200021222211
43003130333021323301033
53230030023102201221
644322151001451251
72554250110565215
oct303347711736117
952500756607884
1013431422303311
114309263808701
12160b1241a0b27
13765768248c2c
143461274accb5
151845ae9a76e1
hexc373f27bc4f

13431422303311 has 4 divisors (see below), whose sum is σ = 13794433716952. Its totient is φ = 13068410889672.

The previous prime is 13431422303297. The next prime is 13431422303333. The reversal of 13431422303311 is 11330322413431.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 13431422303311 - 25 = 13431422303279 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13431422303911) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 181505706765 + ... + 181505706838.

It is an arithmetic number, because the mean of its divisors is an integer number (3448608429238).

Almost surely, 213431422303311 is an apocalyptic number.

13431422303311 is a deficient number, since it is larger than the sum of its proper divisors (363011413641).

13431422303311 is an equidigital number, since it uses as much as digits as its factorization.

13431422303311 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 363011413640.

The product of its (nonzero) digits is 15552, while the sum is 31.

Adding to 13431422303311 its reverse (11330322413431), we get a palindrome (24761744716742).

The spelling of 13431422303311 in words is "thirteen trillion, four hundred thirty-one billion, four hundred twenty-two million, three hundred three thousand, three hundred eleven".

Divisors: 1 37 363011413603 13431422303311