Base | Representation |
---|---|
bin | 1100001100101101001010… |
… | …0010110010101111111001 |
3 | 1202111012210121221011121121 |
4 | 3003023102202302233321 |
5 | 3224222114034443413 |
6 | 44305325241305241 |
7 | 2553005163634006 |
oct | 303132242625771 |
9 | 52435717834547 |
10 | 13412420234233 |
11 | 43011a2619989 |
12 | 1607500495221 |
13 | 763a2a535787 |
14 | 3452439568ad |
15 | 183d4b65eb8d |
hex | c32d28b2bf9 |
13412420234233 has 2 divisors, whose sum is σ = 13412420234234. Its totient is φ = 13412420234232.
The previous prime is 13412420234203. The next prime is 13412420234237. The reversal of 13412420234233 is 33243202421431.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 13405469177104 + 6951057129 = 3661348^2 + 83373^2 .
It is a cyclic number.
It is not a de Polignac number, because 13412420234233 - 237 = 13274981280761 is a prime.
It is not a weakly prime, because it can be changed into another prime (13412420234237) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6706210117116 + 6706210117117.
It is an arithmetic number, because the mean of its divisors is an integer number (6706210117117).
Almost surely, 213412420234233 is an apocalyptic number.
It is an amenable number.
13412420234233 is a deficient number, since it is larger than the sum of its proper divisors (1).
13412420234233 is an equidigital number, since it uses as much as digits as its factorization.
13412420234233 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 82944, while the sum is 34.
Adding to 13412420234233 its reverse (33243202421431), we get a palindrome (46655622655664).
The spelling of 13412420234233 in words is "thirteen trillion, four hundred twelve billion, four hundred twenty million, two hundred thirty-four thousand, two hundred thirty-three".
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