Base | Representation |
---|---|
bin | 1100001100101101000111… |
… | …1111101001110001000111 |
3 | 1202111012202222121011100212 |
4 | 3003023101333221301013 |
5 | 3224222104210204112 |
6 | 44305324312030035 |
7 | 2553005022426245 |
oct | 303132177516107 |
9 | 52435688534325 |
10 | 13412411022407 |
11 | 43011983a7a01 |
12 | 16074b939231b |
13 | 763a2865b8a7 |
14 | 345242639795 |
15 | 183d4a940522 |
hex | c32d1fe9c47 |
13412411022407 has 2 divisors, whose sum is σ = 13412411022408. Its totient is φ = 13412411022406.
The previous prime is 13412411022379. The next prime is 13412411022421. The reversal of 13412411022407 is 70422011421431.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-13412411022407 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13412411022487) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6706205511203 + 6706205511204.
It is an arithmetic number, because the mean of its divisors is an integer number (6706205511204).
Almost surely, 213412411022407 is an apocalyptic number.
13412411022407 is a deficient number, since it is larger than the sum of its proper divisors (1).
13412411022407 is an equidigital number, since it uses as much as digits as its factorization.
13412411022407 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 10752, while the sum is 32.
Adding to 13412411022407 its reverse (70422011421431), we get a palindrome (83834422443838).
The spelling of 13412411022407 in words is "thirteen trillion, four hundred twelve billion, four hundred eleven million, twenty-two thousand, four hundred seven".
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