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134123110331389 is a prime number
BaseRepresentation
bin11110011111101111111000…
…010110001111001111111101
3122120220001012011111210202021
4132133233320112033033331
5120034433112221101024
61153131150053400141
740152034464234544
oct3637577026171775
9576801164453667
10134123110331389
1139810323221a23
1213061b5a339051
1359ab9a7a6c64a
14251984396b15b
151078cb35e3de4
hex79fbf858f3fd

134123110331389 has 2 divisors, whose sum is σ = 134123110331390. Its totient is φ = 134123110331388.

The previous prime is 134123110331303. The next prime is 134123110331437. The reversal of 134123110331389 is 983133011321431.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 108506180556900 + 25616929774489 = 10416630^2 + 5061317^2 .

It is a cyclic number.

It is not a de Polignac number, because 134123110331389 - 243 = 125327017309181 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (134123110337389) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67061555165694 + 67061555165695.

It is an arithmetic number, because the mean of its divisors is an integer number (67061555165695).

Almost surely, 2134123110331389 is an apocalyptic number.

It is an amenable number.

134123110331389 is a deficient number, since it is larger than the sum of its proper divisors (1).

134123110331389 is an equidigital number, since it uses as much as digits as its factorization.

134123110331389 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 139968, while the sum is 43.

The spelling of 134123110331389 in words is "one hundred thirty-four trillion, one hundred twenty-three billion, one hundred ten million, three hundred thirty-one thousand, three hundred eighty-nine".