134110011401 has 2 divisors, whose sum is σ = 134110011402. Its totient is φ = 134110011400.

The previous prime is 134110011353. The next prime is 134110011433. The reversal of 134110011401 is 104110011431.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 133108225600 + 1001785801 = 364840^2 + 31651^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-134110011401 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 134110011401.

It is not a weakly prime, because it can be changed into another prime (134110011481) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67055005700 + 67055005701.

It is an arithmetic number, because the mean of its divisors is an integer number (67055005701).

Almost surely, 2^134110011401 is an apocalyptic number.

It is an amenable number.

134110011401 is a deficient number, since it is larger than the sum of its proper divisors (1).

134110011401 is an equidigital number, since it uses as much as digits as its factorization.

134110011401 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 48, while the sum is 17.

Adding to 134110011401 its reverse (104110011431), we get a palindrome (238220022832).

The spelling of 134110011401 in words is "one hundred thirty-four billion, one hundred ten million, eleven thousand, four hundred one".