Base | Representation |
---|---|
bin | 11000111110001100… |
… | …00000011110000011 |
3 | 1021121022211100011101 |
4 | 30133012000132003 |
5 | 204424040222441 |
6 | 10054153155231 |
7 | 653140652665 |
oct | 143706003603 |
9 | 37538740141 |
10 | 13406570371 |
11 | 575a728827 |
12 | 27219bbb17 |
13 | 13586a3a9c |
14 | 912760535 |
15 | 536eb2231 |
hex | 31f180783 |
13406570371 has 4 divisors (see below), whose sum is σ = 13407705792. Its totient is φ = 13405434952.
The previous prime is 13406570363. The next prime is 13406570383. The reversal of 13406570371 is 17307560431.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 13406570371 - 23 = 13406570363 is a prime.
It is a super-2 number, since 2×134065703712 (a number of 21 digits) contains 22 as substring.
It is a Duffinian number.
It is a zygodrome in base 2.
It is a self number, because there is not a number n which added to its sum of digits gives 13406570371.
It is not an unprimeable number, because it can be changed into a prime (13406570071) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 549811 + ... + 573676.
It is an arithmetic number, because the mean of its divisors is an integer number (3351926448).
Almost surely, 213406570371 is an apocalyptic number.
13406570371 is a deficient number, since it is larger than the sum of its proper divisors (1135421).
13406570371 is a wasteful number, since it uses less digits than its factorization.
13406570371 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1135420.
The product of its (nonzero) digits is 52920, while the sum is 37.
The spelling of 13406570371 in words is "thirteen billion, four hundred six million, five hundred seventy thousand, three hundred seventy-one".
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