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1340435413 is a prime number
BaseRepresentation
bin100111111100101…
…0110101111010101
310110102021011201001
41033321112233111
510221122413123
6341002103301
745134340652
oct11771265725
93412234631
101340435413
11628705a69
12314aaab31
13184924a65
14ca048c29
157ca2b0ad
hex4fe56bd5

1340435413 has 2 divisors, whose sum is σ = 1340435414. Its totient is φ = 1340435412.

The previous prime is 1340435359. The next prime is 1340435449. The reversal of 1340435413 is 3145340431.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1204992369 + 135443044 = 34713^2 + 11638^2 .

It is a cyclic number.

It is not a de Polignac number, because 1340435413 - 217 = 1340304341 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1340435113) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 670217706 + 670217707.

It is an arithmetic number, because the mean of its divisors is an integer number (670217707).

Almost surely, 21340435413 is an apocalyptic number.

It is an amenable number.

1340435413 is a deficient number, since it is larger than the sum of its proper divisors (1).

1340435413 is an equidigital number, since it uses as much as digits as its factorization.

1340435413 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 8640, while the sum is 28.

The square root of 1340435413 is about 36611.9572407704. The cubic root of 1340435413 is about 1102.5931693175.

Adding to 1340435413 its reverse (3145340431), we get a palindrome (4485775844).

The spelling of 1340435413 in words is "one billion, three hundred forty million, four hundred thirty-five thousand, four hundred thirteen".