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13402000413002 = 28380734942247
BaseRepresentation
bin1100001100000110010101…
…1110010101000101001010
31202110012220110012102000202
43003001211132111011022
53224034244101204002
644300443300332202
72552156030624315
oct303014536250512
952405813172022
1013402000413002
1142a7835930a83
1216054929a4062
13762a59886a96
14344935b4d97c
1518393b9c5502
hexc306579514a

13402000413002 has 8 divisors (see below), whose sum is σ = 20345205446496. Its totient is φ = 6620265264172.

The previous prime is 13402000412963. The next prime is 13402000413017. The reversal of 13402000413002 is 20031400020431.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a super-2 number, since 2×134020004130022 (a number of 27 digits) contains 22 as substring.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 40367470958 + ... + 40367471289.

It is an arithmetic number, because the mean of its divisors is an integer number (2543150680812).

Almost surely, 213402000413002 is an apocalyptic number.

13402000413002 is a deficient number, since it is larger than the sum of its proper divisors (6943205033494).

13402000413002 is an equidigital number, since it uses as much as digits as its factorization.

13402000413002 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 80734942332.

The product of its (nonzero) digits is 576, while the sum is 20.

Adding to 13402000413002 its reverse (20031400020431), we get a palindrome (33433400433433).

The spelling of 13402000413002 in words is "thirteen trillion, four hundred two billion, four hundred thirteen thousand, two".

Divisors: 1 2 83 166 80734942247 161469884494 6701000206501 13402000413002