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134012424040000 = 2654111792516779
BaseRepresentation
bin11110011110001000110010…
…111011100010111001000000
3122120111110111020201121120121
4132132020302323202321000
5120031124421023240000
61153004242510150024
740141035540256552
oct3636106273427100
9576443436647517
10134012424040000
1139778393745a50
12130446097b2314
1359a1418322c7c
14251434357b4d2
151075e86135b1a
hex79e232ee2e40

134012424040000 has 560 divisors, whose sum is σ = 366048591955200. Its totient is φ = 48259360000000.

The previous prime is 134012424039943. The next prime is 134012424040073. The reversal of 134012424040000 is 40424210431.

It is a Harshad number since it is a multiple of its sum of digits (25).

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 79 ways as a sum of consecutive naturals, for example, 19768756611 + ... + 19768763389.

It is an arithmetic number, because the mean of its divisors is an integer number (653658199920).

Almost surely, 2134012424040000 is an apocalyptic number.

134012424040000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 134012424040000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (183024295977600).

134012424040000 is an abundant number, since it is smaller than the sum of its proper divisors (232036167915200).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

134012424040000 is a wasteful number, since it uses less digits than its factorization.

134012424040000 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 7252 (or 7227 counting only the distinct ones).

The product of its (nonzero) digits is 3072, while the sum is 25.

Adding to 134012424040000 its reverse (40424210431), we get a palindrome (134052848250431).

The spelling of 134012424040000 in words is "one hundred thirty-four trillion, twelve billion, four hundred twenty-four million, forty thousand".