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1340122201000 = 235311283742943
BaseRepresentation
bin10011100000000101100…
…000011111101110101000
311202010002102100102222121
4103200011200133232220
5133424032240413000
62503351005401024
7165551322521332
oct23400540375650
94663072312877
101340122201000
114773850556a0
12197884269174
13994b059468b
1448c10086452
1524cd64e9b1a
hex1380581fba8

1340122201000 has 128 divisors (see below), whose sum is σ = 3422252021760. Its totient is φ = 487134048000.

The previous prime is 1340122200997. The next prime is 1340122201003. The reversal of 1340122201000 is 1022210431.

It is an interprime number because it is at equal distance from previous prime (1340122200997) and next prime (1340122201003).

It is a super-2 number, since 2×13401222010002 (a number of 25 digits) contains 22 as substring.

It is not an unprimeable number, because it can be changed into a prime (1340122201003) by changing a digit.

It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 31185529 + ... + 31228471.

It is an arithmetic number, because the mean of its divisors is an integer number (26736343920).

Almost surely, 21340122201000 is an apocalyptic number.

1340122201000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 1340122201000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (1711126010880).

1340122201000 is an abundant number, since it is smaller than the sum of its proper divisors (2082129820760).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

1340122201000 is a wasteful number, since it uses less digits than its factorization.

1340122201000 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 45812 (or 45798 counting only the distinct ones).

The product of its (nonzero) digits is 96, while the sum is 16.

Adding to 1340122201000 its reverse (1022210431), we get a palindrome (1341144411431).

The spelling of 1340122201000 in words is "one trillion, three hundred forty billion, one hundred twenty-two million, two hundred one thousand".

Divisors: 1 2 4 5 8 10 11 20 22 25 40 44 50 55 88 100 110 125 200 220 250 275 440 500 550 1000 1100 1375 2200 2750 2837 5500 5674 11000 11348 14185 22696 28370 31207 42943 56740 62414 70925 85886 113480 124828 141850 156035 171772 214715 249656 283700 312070 343544 354625 429430 472373 567400 624140 709250 780175 858860 944746 1073575 1248280 1418500 1560350 1717720 1889492 2147150 2361865 2837000 3120700 3778984 3900875 4294300 4723730 5367875 6241400 7801750 8588600 9447460 10735750 11809325 15603500 18894920 21471500 23618650 31207000 42943000 47237300 59046625 94474600 118093250 121829291 236186500 243658582 472373000 487317164 609146455 974634328 1218292910 1340122201 2436585820 2680244402 3045732275 4873171640 5360488804 6091464550 6700611005 10720977608 12182929100 13401222010 15228661375 24365858200 26802444020 30457322750 33503055025 53604888040 60914645500 67006110050 121829291000 134012220100 167515275125 268024440200 335030550250 670061100500 1340122201000