Base | Representation |
---|---|
bin | 11110010111001000100111… |
… | …110101011001001111001000 |
3 | 122111210110101000200210022110 |
4 | 132113020213311121033020 |
5 | 120000233400043303224 |
6 | 1151555215342022320 |
7 | 40061211440441235 |
oct | 3627104765311710 |
9 | 574713330623273 |
10 | 133531201541064 |
11 | 396022a0133a78 |
12 | 12b872a92779a0 |
13 | 5967c2750b992 |
14 | 24d8d3213478c |
15 | 10686bdc8b929 |
hex | 797227d593c8 |
133531201541064 has 32 divisors (see below), whose sum is σ = 333835022701440. Its totient is φ = 44509464667200.
The previous prime is 133531201541041. The next prime is 133531201541069. The reversal of 133531201541064 is 460145102135331.
It is not an unprimeable number, because it can be changed into a prime (133531201541069) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 57324672 + ... + 59608559.
It is an arithmetic number, because the mean of its divisors is an integer number (10432344459420).
Almost surely, 2133531201541064 is an apocalyptic number.
It is an amenable number.
133531201541064 is an abundant number, since it is smaller than the sum of its proper divisors (200303821160376).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
133531201541064 is a wasteful number, since it uses less digits than its factorization.
133531201541064 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 116980821 (or 116980817 counting only the distinct ones).
The product of its (nonzero) digits is 129600, while the sum is 39.
Adding to 133531201541064 its reverse (460145102135331), we get a palindrome (593676303676395).
The spelling of 133531201541064 in words is "one hundred thirty-three trillion, five hundred thirty-one billion, two hundred one million, five hundred forty-one thousand, sixty-four".
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