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133403141213 is a prime number
BaseRepresentation
bin111110000111101110…
…0100110010001011101
3110202100002112201201222
41330033130212101131
54141202201004323
6141141244143125
712431565663566
oct1741734462135
9422302481658
10133403141213
1151637660531
1221a30537aa5
13c76cc5a364
14665745316d
15370b9db9c8
hex1f0f72645d

133403141213 has 2 divisors, whose sum is σ = 133403141214. Its totient is φ = 133403141212.

The previous prime is 133403141189. The next prime is 133403141227. The reversal of 133403141213 is 312141304331.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 115546966084 + 17856175129 = 339922^2 + 133627^2 .

It is an emirp because it is prime and its reverse (312141304331) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 133403141213 - 218 = 133402879069 is a prime.

It is a super-2 number, since 2×1334031412132 (a number of 23 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (133403141713) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66701570606 + 66701570607.

It is an arithmetic number, because the mean of its divisors is an integer number (66701570607).

Almost surely, 2133403141213 is an apocalyptic number.

It is an amenable number.

133403141213 is a deficient number, since it is larger than the sum of its proper divisors (1).

133403141213 is an equidigital number, since it uses as much as digits as its factorization.

133403141213 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 2592, while the sum is 26.

Adding to 133403141213 its reverse (312141304331), we get a palindrome (445544445544).

The spelling of 133403141213 in words is "one hundred thirty-three billion, four hundred three million, one hundred forty-one thousand, two hundred thirteen".