Base | Representation |
---|---|
bin | 1100000111111010111111… |
… | …0011011011111110001111 |
3 | 1202012100122212011220112121 |
4 | 3001332233303123332033 |
5 | 3221400304123004312 |
6 | 44203454032113411 |
7 | 2544035413050322 |
oct | 301765763337617 |
9 | 52170585156477 |
10 | 13330233016207 |
11 | 427a3580235a8 |
12 | 15b35a4095867 |
13 | 759060226213 |
14 | 34128850a7b9 |
15 | 181b3b14b707 |
hex | c1fafcdbf8f |
13330233016207 has 2 divisors, whose sum is σ = 13330233016208. Its totient is φ = 13330233016206.
The previous prime is 13330233016157. The next prime is 13330233016223. The reversal of 13330233016207 is 70261033203331.
It is a strong prime.
It is an emirp because it is prime and its reverse (70261033203331) is a distict prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-13330233016207 is a prime.
It is a super-2 number, since 2×133302330162072 (a number of 27 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13330233016007) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6665116508103 + 6665116508104.
It is an arithmetic number, because the mean of its divisors is an integer number (6665116508104).
Almost surely, 213330233016207 is an apocalyptic number.
13330233016207 is a deficient number, since it is larger than the sum of its proper divisors (1).
13330233016207 is an equidigital number, since it uses as much as digits as its factorization.
13330233016207 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 40824, while the sum is 34.
Adding to 13330233016207 its reverse (70261033203331), we get a palindrome (83591266219538).
The spelling of 13330233016207 in words is "thirteen trillion, three hundred thirty billion, two hundred thirty-three million, sixteen thousand, two hundred seven".
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