1332343340401 has 2 divisors, whose sum is σ = 1332343340402. Its totient is φ = 1332343340400.

The previous prime is 1332343340399. The next prime is 1332343340443. The reversal of 1332343340401 is 1040433432331.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1200865305600 + 131478034801 = 1095840^2 + 362599^2 .

It is a cyclic number.

It is not a de Polignac number, because 1332343340401 - 2¹ = 1332343340399 is a prime.

It is a super-3 number, since 3×1332343340401³ (a number of 37 digits) contains 333 as substring.

Together with 1332343340399, it forms a pair of twin primes.

It is not a weakly prime, because it can be changed into another prime (1332343340201) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 666171670200 + 666171670201.

It is an arithmetic number, because the mean of its divisors is an integer number (666171670201).

Almost surely, 2^{1332343340401} is an apocalyptic number.

It is an amenable number.

1332343340401 is a deficient number, since it is larger than the sum of its proper divisors (1).

1332343340401 is an equidigital number, since it uses as much as digits as its factorization.

1332343340401 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 31104, while the sum is 31.

Adding to 1332343340401 its reverse (1040433432331), we get a palindrome (2372776772732).

The spelling of 1332343340401 in words is "one trillion, three hundred thirty-two billion, three hundred forty-three million, three hundred forty thousand, four hundred one".