Base | Representation |
---|---|
bin | 1100000111011001100000… |
… | …0001111001111011010110 |
3 | 1202011111110102011210210212 |
4 | 3001312120001321323112 |
5 | 3221223402010034032 |
6 | 44155410051045422 |
7 | 2543266564414604 |
oct | 301663001717326 |
9 | 52144412153725 |
10 | 13321244221142 |
11 | 4276565095850 |
12 | 15b18b58a0872 |
13 | 758259b9a080 |
14 | 340a747b0874 |
15 | 1817b1e34bb2 |
hex | c1d98079ed6 |
13321244221142 has 32 divisors (see below), whose sum is σ = 24495860471040. Its totient is φ = 5346318748320.
The previous prime is 13321244221127. The next prime is 13321244221231. The reversal of 13321244221142 is 24112244212331.
13321244221142 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a junction number, because it is equal to n+sod(n) for n = 13321244221099 and 13321244221108.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 1012553792 + ... + 1012566947.
It is an arithmetic number, because the mean of its divisors is an integer number (765495639720).
Almost surely, 213321244221142 is an apocalyptic number.
13321244221142 is a deficient number, since it is larger than the sum of its proper divisors (11174616249898).
13321244221142 is a wasteful number, since it uses less digits than its factorization.
13321244221142 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2025120788.
The product of its digits is 18432, while the sum is 32.
Adding to 13321244221142 its reverse (24112244212331), we get a palindrome (37433488433473).
The spelling of 13321244221142 in words is "thirteen trillion, three hundred twenty-one billion, two hundred forty-four million, two hundred twenty-one thousand, one hundred forty-two".
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