Base | Representation |
---|---|
bin | 11110010001011101100111… |
… | …010010100000011011111010 |
3 | 122110102012021202200220021221 |
4 | 132101131213102200123322 |
5 | 114422342114033112102 |
6 | 1151100154215022254 |
7 | 40021102415121145 |
oct | 3621354722403372 |
9 | 573365252626257 |
10 | 133141424113402 |
11 | 39471a62a16571 |
12 | 12b2384966a98a |
13 | 593a24aa19313 |
14 | 24c41178b105c |
15 | 105d4a9a68637 |
hex | 7917674a06fa |
133141424113402 has 4 divisors (see below), whose sum is σ = 199712136170106. Its totient is φ = 66570712056700.
The previous prime is 133141424113303. The next prime is 133141424113457. The reversal of 133141424113402 is 204311424141331.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in only one way, i.e., 133138851493561 + 2572619841 = 11538581^2 + 50721^2 .
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 33285356028349 + ... + 33285356028352.
Almost surely, 2133141424113402 is an apocalyptic number.
133141424113402 is a deficient number, since it is larger than the sum of its proper divisors (66570712056704).
133141424113402 is an equidigital number, since it uses as much as digits as its factorization.
133141424113402 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 66570712056703.
The product of its (nonzero) digits is 27648, while the sum is 34.
Adding to 133141424113402 its reverse (204311424141331), we get a palindrome (337452848254733).
The spelling of 133141424113402 in words is "one hundred thirty-three trillion, one hundred forty-one billion, four hundred twenty-four million, one hundred thirteen thousand, four hundred two".
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