13311243203413 has 4 divisors (see below), whose sum is σ = 13408405562700. Its totient is φ = 13214080844128.

The previous prime is 13311243203399. The next prime is 13311243203437. The reversal of 13311243203413 is 31430234211331.

13311243203413 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 6183587369124 + 7127655834289 = 2486682^2 + 2669767^2 .

It is a cyclic number.

It is not a de Polignac number, because 13311243203413 - 2²⁹ = 13310706332501 is a prime.

It is a super-3 number, since 3×13311243203413³ (a number of 40 digits) contains 333 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13311243203113) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 48581179438 + ... + 48581179711.

It is an arithmetic number, because the mean of its divisors is an integer number (3352101390675).

Almost surely, 2^{13311243203413} is an apocalyptic number.

It is an amenable number.

13311243203413 is a deficient number, since it is larger than the sum of its proper divisors (97162359287).

13311243203413 is an equidigital number, since it uses as much as digits as its factorization.

13311243203413 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 97162359286.

The product of its (nonzero) digits is 15552, while the sum is 31.

Adding to 13311243203413 its reverse (31430234211331), we get a palindrome (44741477414744).

The spelling of 13311243203413 in words is "thirteen trillion, three hundred eleven billion, two hundred forty-three million, two hundred three thousand, four hundred thirteen".