Base | Representation |
---|---|
bin | 11000110010110100… |
… | …10110111000000011 |
3 | 1021100200110010212000 |
4 | 30121122112320003 |
5 | 204230134213411 |
6 | 10040510035043 |
7 | 650602454634 |
oct | 143132267003 |
9 | 37320403760 |
10 | 13311241731 |
11 | 5710937a27 |
12 | 26b5aa8a83 |
13 | 1341a075c8 |
14 | 903c2788b |
15 | 52d931956 |
hex | 319696e03 |
13311241731 has 32 divisors (see below), whose sum is σ = 19893888000. Its totient is φ = 8796281184.
The previous prime is 13311241709. The next prime is 13311241733. The reversal of 13311241731 is 13714211331.
13311241731 is a `hidden beast` number, since 133 + 112 + 417 + 3 + 1 = 666.
It is not a de Polignac number, because 13311241731 - 230 = 12237499907 is a prime.
It is a super-2 number, since 2×133112417312 (a number of 21 digits) contains 22 as substring.
It is a Harshad number since it is a multiple of its sum of digits (27).
It is a junction number, because it is equal to n+sod(n) for n = 13311241695 and 13311241704.
It is not an unprimeable number, because it can be changed into a prime (13311241733) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 2695941 + ... + 2700873.
It is an arithmetic number, because the mean of its divisors is an integer number (621684000).
Almost surely, 213311241731 is an apocalyptic number.
13311241731 is a deficient number, since it is larger than the sum of its proper divisors (6582646269).
13311241731 is a wasteful number, since it uses less digits than its factorization.
13311241731 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 5800 (or 5794 counting only the distinct ones).
The product of its digits is 1512, while the sum is 27.
The spelling of 13311241731 in words is "thirteen billion, three hundred eleven million, two hundred forty-one thousand, seven hundred thirty-one".
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