Search a number
-
+
13255652033 = 138312285127
BaseRepresentation
bin11000101100001100…
…10011001011000001
31021012210211220010022
430112012103023001
5204121421331113
610031202343225
7646326116561
oct142606231301
937183756108
1013255652033
115692519628
12269b35ab15
131333342bb0
148da6b6da1
15528b00908
hex3161932c1

13255652033 has 8 divisors (see below), whose sum is σ = 14447310528. Its totient is φ = 12088563984.

The previous prime is 13255652027. The next prime is 13255652087. The reversal of 13255652033 is 33025655231.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 13255652033 - 216 = 13255586497 is a prime.

It is a super-3 number, since 3×132556520333 (a number of 31 digits) contains 333 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 13255651984 and 13255652002.

It is not an unprimeable number, because it can be changed into a prime (13255652533) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 6141485 + ... + 6143642.

It is an arithmetic number, because the mean of its divisors is an integer number (1805913816).

Almost surely, 213255652033 is an apocalyptic number.

13255652033 is a gapful number since it is divisible by the number (13) formed by its first and last digit.

It is an amenable number.

13255652033 is a deficient number, since it is larger than the sum of its proper divisors (1191658495).

13255652033 is a wasteful number, since it uses less digits than its factorization.

13255652033 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 12285223.

The product of its (nonzero) digits is 81000, while the sum is 35.

The spelling of 13255652033 in words is "thirteen billion, two hundred fifty-five million, six hundred fifty-two thousand, thirty-three".

Divisors: 1 13 83 1079 12285127 159706651 1019665541 13255652033