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1324442311132 = 22331110577783
BaseRepresentation
bin10011010001011110111…
…010011101100111011100
311200121121122212111201211
4103101132322131213130
5133144424212424012
62452235043114204
7164454625615603
oct23213672354734
94617548774654
101324442311132
1147076917a326
12194829072964
1397b81c2a835
1448163840a3a
15246b9b866a7
hex1345ee9d9dc

1324442311132 has 6 divisors (see below), whose sum is σ = 2317774044488. Its totient is φ = 662221155564.

The previous prime is 1324442311103. The next prime is 1324442311133. The reversal of 1324442311132 is 2311132444231.

It is a happy number.

It is a super-2 number, since 2×13244423111322 (a number of 25 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1324442311094 and 1324442311103.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1324442311133) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 165555288888 + ... + 165555288895.

Almost surely, 21324442311132 is an apocalyptic number.

It is an amenable number.

1324442311132 is a deficient number, since it is larger than the sum of its proper divisors (993331733356).

1324442311132 is a wasteful number, since it uses less digits than its factorization.

1324442311132 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 331110577787 (or 331110577785 counting only the distinct ones).

The product of its digits is 13824, while the sum is 31.

Adding to 1324442311132 its reverse (2311132444231), we get a palindrome (3635574755363).

The spelling of 1324442311132 in words is "one trillion, three hundred twenty-four billion, four hundred forty-two million, three hundred eleven thousand, one hundred thirty-two".

Divisors: 1 2 4 331110577783 662221155566 1324442311132