Base | Representation |
---|---|
bin | 11110000100101000101110… |
… | …111110110100110100010110 |
3 | 122100021221012120200022021102 |
4 | 132010220232332310310112 |
5 | 114313422000322243410 |
6 | 1145143224343550102 |
7 | 36600320241323540 |
oct | 3604505676646426 |
9 | 570257176608242 |
10 | 132260011134230 |
11 | 39162179301611 |
12 | 12a00a6215b332 |
13 | 58a50b0c937b5 |
14 | 24935c0c80690 |
15 | 10455be1ec2a5 |
hex | 784a2efb4d16 |
132260011134230 has 64 divisors (see below), whose sum is σ = 282576229447680. Its totient is φ = 43629246409344.
The previous prime is 132260011134143. The next prime is 132260011134281. The reversal of 132260011134230 is 32431110062231.
It is a junction number, because it is equal to n+sod(n) for n = 132260011134193 and 132260011134202.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 340489037 + ... + 340877256.
It is an arithmetic number, because the mean of its divisors is an integer number (4415253585120).
Almost surely, 2132260011134230 is an apocalyptic number.
132260011134230 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
132260011134230 is an abundant number, since it is smaller than the sum of its proper divisors (150316218313450).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
132260011134230 is a wasteful number, since it uses less digits than its factorization.
132260011134230 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 681366413.
The product of its (nonzero) digits is 5184, while the sum is 29.
Adding to 132260011134230 its reverse (32431110062231), we get a palindrome (164691121196461).
The spelling of 132260011134230 in words is "one hundred thirty-two trillion, two hundred sixty billion, eleven million, one hundred thirty-four thousand, two hundred thirty".
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