Base | Representation |
---|---|
bin | 1100000001110100010010… |
… | …0111101000001111001111 |
3 | 1201211022221202201021120201 |
4 | 3000131010213220033033 |
5 | 3213141012004343003 |
6 | 44043351111554331 |
7 | 2533333432202635 |
oct | 300350447501717 |
9 | 51738852637521 |
10 | 13225355543503 |
11 | 4239929469024 |
12 | 15971b498b9a7 |
13 | 74c1b808826c |
14 | 33a1797a1355 |
15 | 17e04db0eb1d |
hex | c07449e83cf |
13225355543503 has 2 divisors, whose sum is σ = 13225355543504. Its totient is φ = 13225355543502.
The previous prime is 13225355543483. The next prime is 13225355543537. The reversal of 13225355543503 is 30534555352231.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 13225355543503 - 25 = 13225355543471 is a prime.
It is a super-2 number, since 2×132253555435032 (a number of 27 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13225355543903) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6612677771751 + 6612677771752.
It is an arithmetic number, because the mean of its divisors is an integer number (6612677771752).
Almost surely, 213225355543503 is an apocalyptic number.
13225355543503 is a deficient number, since it is larger than the sum of its proper divisors (1).
13225355543503 is an equidigital number, since it uses as much as digits as its factorization.
13225355543503 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 4050000, while the sum is 46.
The spelling of 13225355543503 in words is "thirteen trillion, two hundred twenty-five billion, three hundred fifty-five million, five hundred forty-three thousand, five hundred three".
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