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132245015443 is a prime number
BaseRepresentation
bin111101100101001101…
…0101100101110010011
3110122100101022211211221
41323022122230232103
54131314210443233
6140430313345511
712361104040612
oct1731232545623
9418311284757
10132245015443
11510a29554a2
1221768708297
13c617037838
146587703879
15368eec342d
hex1eca6acb93

132245015443 has 2 divisors, whose sum is σ = 132245015444. Its totient is φ = 132245015442.

The previous prime is 132245015393. The next prime is 132245015479. The reversal of 132245015443 is 344510542231.

It is a strong prime.

It is an emirp because it is prime and its reverse (344510542231) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 132245015443 - 217 = 132244884371 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 132245015399 and 132245015408.

It is not a weakly prime, because it can be changed into another prime (132245016443) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66122507721 + 66122507722.

It is an arithmetic number, because the mean of its divisors is an integer number (66122507722).

Almost surely, 2132245015443 is an apocalyptic number.

132245015443 is a deficient number, since it is larger than the sum of its proper divisors (1).

132245015443 is an equidigital number, since it uses as much as digits as its factorization.

132245015443 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 57600, while the sum is 34.

Adding to 132245015443 its reverse (344510542231), we get a palindrome (476755557674).

The spelling of 132245015443 in words is "one hundred thirty-two billion, two hundred forty-five million, fifteen thousand, four hundred forty-three".