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132245013431 is a prime number
BaseRepresentation
bin111101100101001101…
…0101100001110110111
3110122100101022202002102
41323022122230032313
54131314210412211
6140430313332315
712361104032006
oct1731232541667
9418311282072
10132245013431
11510a2953a33
122176870709b
13c61703694b
146587702c3d
15368eec2a3b
hex1eca6ac3b7

132245013431 has 2 divisors, whose sum is σ = 132245013432. Its totient is φ = 132245013430.

The previous prime is 132245013419. The next prime is 132245013437. The reversal of 132245013431 is 134310542231.

It is a strong prime.

It is an emirp because it is prime and its reverse (134310542231) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 132245013431 - 214 = 132244997047 is a prime.

It is a super-2 number, since 2×1322450134312 (a number of 23 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 132245013394 and 132245013403.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (132245013437) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66122506715 + 66122506716.

It is an arithmetic number, because the mean of its divisors is an integer number (66122506716).

Almost surely, 2132245013431 is an apocalyptic number.

132245013431 is a deficient number, since it is larger than the sum of its proper divisors (1).

132245013431 is an equidigital number, since it uses as much as digits as its factorization.

132245013431 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 8640, while the sum is 29.

Adding to 132245013431 its reverse (134310542231), we get a palindrome (266555555662).

The spelling of 132245013431 in words is "one hundred thirty-two billion, two hundred forty-five million, thirteen thousand, four hundred thirty-one".