Base | Representation |
---|---|
bin | 111101100101001101… |
… | …0101100000000110101 |
3 | 110122100101022200212011 |
4 | 1323022122230000311 |
5 | 4131314210400113 |
6 | 140430313324221 |
7 | 12361104026254 |
oct | 1731232540065 |
9 | 418311280764 |
10 | 132245012533 |
11 | 510a2953297 |
12 | 21768706671 |
13 | c61703640a |
14 | 658770279b |
15 | 368eec263d |
hex | 1eca6ac035 |
132245012533 has 2 divisors, whose sum is σ = 132245012534. Its totient is φ = 132245012532.
The previous prime is 132245012527. The next prime is 132245012591. The reversal of 132245012533 is 335210542231.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 96781343409 + 35463669124 = 311097^2 + 188318^2 .
It is a cyclic number.
It is not a de Polignac number, because 132245012533 - 29 = 132245012021 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 132245012495 and 132245012504.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (132245012503) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66122506266 + 66122506267.
It is an arithmetic number, because the mean of its divisors is an integer number (66122506267).
Almost surely, 2132245012533 is an apocalyptic number.
It is an amenable number.
132245012533 is a deficient number, since it is larger than the sum of its proper divisors (1).
132245012533 is an equidigital number, since it uses as much as digits as its factorization.
132245012533 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 21600, while the sum is 31.
Adding to 132245012533 its reverse (335210542231), we get a palindrome (467455554764).
The spelling of 132245012533 in words is "one hundred thirty-two billion, two hundred forty-five million, twelve thousand, five hundred thirty-three".
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