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13222301113 = 71888900159
BaseRepresentation
bin11000101000001110…
…00100110110111001
31021010111002111021001
430110013010312321
5204034402113423
610024011445001
7645442463560
oct142407046671
937114074231
1013222301113
11567570a58a
122690156761
131329466918
148d60b4bd7
15525c13cad
hex3141c4db9

13222301113 has 4 divisors (see below), whose sum is σ = 15111201280. Its totient is φ = 11333400948.

The previous prime is 13222301107. The next prime is 13222301119. The reversal of 13222301113 is 31110322231.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 31110322231 = 162389191579.

It is an interprime number because it is at equal distance from previous prime (13222301107) and next prime (13222301119).

It is a cyclic number.

It is not a de Polignac number, because 13222301113 - 29 = 13222300601 is a prime.

It is not an unprimeable number, because it can be changed into a prime (13222301119) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 944450073 + ... + 944450086.

It is an arithmetic number, because the mean of its divisors is an integer number (3777800320).

Almost surely, 213222301113 is an apocalyptic number.

It is an amenable number.

13222301113 is a deficient number, since it is larger than the sum of its proper divisors (1888900167).

13222301113 is an equidigital number, since it uses as much as digits as its factorization.

13222301113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1888900166.

The product of its (nonzero) digits is 216, while the sum is 19.

Adding to 13222301113 its reverse (31110322231), we get a palindrome (44332623344).

The spelling of 13222301113 in words is "thirteen billion, two hundred twenty-two million, three hundred one thousand, one hundred thirteen".

Divisors: 1 7 1888900159 13222301113