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13204545231 = 34401515077
BaseRepresentation
bin11000100110000110…
…10101111011001111
31021002020200101202210
430103003111323033
5204020330421411
610022135121503
7645135532263
oct142303257317
937066611683
1013204545231
1156666922a9
122686213293
13132588aa97
148d39b20a3
155243a7ca6
hex3130d5ecf

13204545231 has 4 divisors (see below), whose sum is σ = 17606060312. Its totient is φ = 8803030152.

The previous prime is 13204545229. The next prime is 13204545251. The reversal of 13204545231 is 13254540231.

It is a semiprime because it is the product of two primes.

It is not a de Polignac number, because 13204545231 - 21 = 13204545229 is a prime.

It is a super-2 number, since 2×132045452312 (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13204545251) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2200757536 + ... + 2200757541.

It is an arithmetic number, because the mean of its divisors is an integer number (4401515078).

Almost surely, 213204545231 is an apocalyptic number.

13204545231 is a deficient number, since it is larger than the sum of its proper divisors (4401515081).

13204545231 is an equidigital number, since it uses as much as digits as its factorization.

13204545231 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 4401515080.

The product of its (nonzero) digits is 14400, while the sum is 30.

Subtracting 13204545231 from its reverse (13254540231), we obtain a triangular number (49995000 = T9999).

The spelling of 13204545231 in words is "thirteen billion, two hundred four million, five hundred forty-five thousand, two hundred thirty-one".

Divisors: 1 3 4401515077 13204545231