132013535350441 has 2 divisors, whose sum is σ = 132013535350442. Its totient is φ = 132013535350440.

The previous prime is 132013535350387. The next prime is 132013535350453. The reversal of 132013535350441 is 144053535310231.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 130887328360000 + 1126206990441 = 11440600^2 + 1061229^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-132013535350441 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 132013535350394 and 132013535350403.

It is not a weakly prime, because it can be changed into another prime (132013535390441) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66006767675220 + 66006767675221.

It is an arithmetic number, because the mean of its divisors is an integer number (66006767675221).

Almost surely, 2^{132013535350441} is an apocalyptic number.

It is an amenable number.

132013535350441 is a deficient number, since it is larger than the sum of its proper divisors (1).

132013535350441 is an equidigital number, since it uses as much as digits as its factorization.

132013535350441 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 324000, while the sum is 40.

The spelling of 132013535350441 in words is "one hundred thirty-two trillion, thirteen billion, five hundred thirty-five million, three hundred fifty thousand, four hundred forty-one".