Base | Representation |
---|---|
bin | 111101001111111010… |
… | …1011111110010001011 |
3 | 110120111121001210121001 |
4 | 1322133311133302023 |
5 | 4123333314320133 |
6 | 140231353355431 |
7 | 12334310552314 |
oct | 1723765376213 |
9 | 416447053531 |
10 | 131530620043 |
11 | 50866673679 |
12 | 215a9408b77 |
13 | c532028074 |
14 | 651a89d60b |
15 | 364c40a87d |
hex | 1e9fd5fc8b |
131530620043 has 2 divisors, whose sum is σ = 131530620044. Its totient is φ = 131530620042.
The previous prime is 131530620019. The next prime is 131530620071. The reversal of 131530620043 is 340026035131.
It is an a-pointer prime, because the next prime (131530620071) can be obtained adding 131530620043 to its sum of digits (28).
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 131530620043 - 233 = 122940685451 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 131530619993 and 131530620020.
It is not a weakly prime, because it can be changed into another prime (131530620343) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65765310021 + 65765310022.
It is an arithmetic number, because the mean of its divisors is an integer number (65765310022).
Almost surely, 2131530620043 is an apocalyptic number.
131530620043 is a deficient number, since it is larger than the sum of its proper divisors (1).
131530620043 is an equidigital number, since it uses as much as digits as its factorization.
131530620043 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 6480, while the sum is 28.
Adding to 131530620043 its reverse (340026035131), we get a palindrome (471556655174).
The spelling of 131530620043 in words is "one hundred thirty-one billion, five hundred thirty million, six hundred twenty thousand, forty-three".
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