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131530620043 is a prime number
BaseRepresentation
bin111101001111111010…
…1011111110010001011
3110120111121001210121001
41322133311133302023
54123333314320133
6140231353355431
712334310552314
oct1723765376213
9416447053531
10131530620043
1150866673679
12215a9408b77
13c532028074
14651a89d60b
15364c40a87d
hex1e9fd5fc8b

131530620043 has 2 divisors, whose sum is σ = 131530620044. Its totient is φ = 131530620042.

The previous prime is 131530620019. The next prime is 131530620071. The reversal of 131530620043 is 340026035131.

It is an a-pointer prime, because the next prime (131530620071) can be obtained adding 131530620043 to its sum of digits (28).

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 131530620043 - 233 = 122940685451 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 131530619993 and 131530620020.

It is not a weakly prime, because it can be changed into another prime (131530620343) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65765310021 + 65765310022.

It is an arithmetic number, because the mean of its divisors is an integer number (65765310022).

Almost surely, 2131530620043 is an apocalyptic number.

131530620043 is a deficient number, since it is larger than the sum of its proper divisors (1).

131530620043 is an equidigital number, since it uses as much as digits as its factorization.

131530620043 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 6480, while the sum is 28.

Adding to 131530620043 its reverse (340026035131), we get a palindrome (471556655174).

The spelling of 131530620043 in words is "one hundred thirty-one billion, five hundred thirty million, six hundred twenty thousand, forty-three".